Advertisements
Advertisements
Question
Draw the structure of the given derivative.
Acetaldehydedimethylacetal
Advertisements
Solution 1
\[\begin{array}{cc}
\phantom{..................}\ce{OCH3}\\
\phantom{...........}/\\
\ce{CH3 - CH}\\
\phantom{...........}\backslash\\
\phantom{..................}\ce{OCH3}\end{array}\]
Solution 2
\[\begin{array}{cc}
\phantom{...}\ce{CH3}\phantom{...}\ce{OCH3}\\
\backslash\phantom{..}/\\
\ce{C}\\
/\phantom{..}\backslash\\
\phantom{.....}\ce{H}\phantom{....}\ce{OCH3}\
\end{array}\]
APPEARS IN
RELATED QUESTIONS
Why carboxylic acid does not give reactions of carbonyl group?
Account for the following:
Aromatic carboxylic acids do not undergo Friedel-Crafts reaction.
\[\begin{array}{cc}
\ce{CH3 - C ≡ CH ->[40{%} H2SO4][1{%} HgSO4] A ->[Isomerisation] CH3 - C - CH3}\\
\phantom{........................................}||\\
\phantom{........................................}\ce{O}\\
\end{array}\]
Structure of ‘A’ and type of isomerism in the above reaction are respectively.
In HVZ reactions, the substitution takes place at:
Draw the structures of the given compound - 3-Bromo-4-phenylpentanoic acid
Draw the structure of the following compound.
3-Bromo-4-phenylpentanoic acid
Draw the structure of the following compound.
3-Bromo-4-phenylpentanoic acid
Draw the structure of the given compound.
3-Bromo-4-phenylpentanoic acid
Draw the structure of the following compound.
3-Bromo-4-phenylpentanoic acid
