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Question
Draw the graphs of the following equations on the same graph paper:
2x + 3y = 12
x – y = 1.
Find the coordinates of the vertices of the triangle formed by the two straight lines and the y-axis.
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Solution
The given equations are
2x + 3y = 12 ......(i)
x − y = 1 .....(ii)
Putting x = 0 in equation (i) weget
`=> 2 xx 0 + 3y = 12`
`=> y = 4`
x = 0, y = 4
Putting y = 0 in equation (i) we get
`=> x + 3 xx 0 = 6`
`=> x = 6, y = 0`
Use the following table to draw the graph.
| x | 0 | 6 |
| y | 4 | 0 |
Draw the graph by plotting the two points A(0, 2) and B(6, 0) from table

x - y = 1 .....(ii)
Putting x = 0 in equation (ii) we get
`=> 0 - y = 1`
`=> y = -1`
x = 0, y = -1
Putting y = 0 in equation (ii) we get
`=> x - 0 = 1`
`=> x = 1`
x = 1, y = 0
Use the following table to draw the graph.
| x | 0 | 1 |
| y | -1 | 0 |
Draw the graph by plotting the two points C(0, -1), D(1, 0) from table.
Draw the graph by plotting the two points from the table.
The intersection point is P(3, 2).
Three points of the triangle are A(0, 4), C(0, -1) and P(3, 2).
Hence the value of x = 3 and y = 2.
