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Maharashtra State BoardSSC (English Medium) 8th Standard

Divide. Write the quotient and the remainder. 40a3 ÷ (−10a) - Mathematics

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Question

Divide. Write the quotient and the remainder.

40a3 ÷ (−10a)

Sum
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Solution

40a3 ÷ (−10a)

\[= \frac{40 a^3}{\left( - 10a \right)}\] 

\[ = \frac{\left( - 4 \right) \times \left( - 10a \right) \times a^2}{\left( - 10a \right)}\] 

\[ =  - 4 a^2\]

So, quotient = \[- 4 a^2\] and remainder = 0

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Chapter 10: Division of Polynomials - Practice Set 10.1 [Page 64]

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Balbharati Mathematics [English] Standard 8 Maharashtra State Board
Chapter 10 Division of Polynomials
Practice Set 10.1 | Q 2 | Page 64
Balbharati Mathematics Integrated [English] Standard 8 Maharashtra State Board
Chapter 10 Division of Polynomials
Practice Set 10.1 | Q 1. (2) | Page 39
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