Advertisements
Advertisements
Question
Divide. Write the quotient and the remainder.
40a3 ÷ (−10a)
Sum
Advertisements
Solution
40a3 ÷ (−10a)
\[= \frac{40 a^3}{\left( - 10a \right)}\]
\[ = \frac{\left( - 4 \right) \times \left( - 10a \right) \times a^2}{\left( - 10a \right)}\]
\[ = - 4 a^2\]
So, quotient = \[- 4 a^2\] and remainder = 0
shaalaa.com
Is there an error in this question or solution?
