Advertisements
Advertisements
Question
Divide −72a4b5c8 by −9a2b2c3.
Advertisements
Solution
\[\frac{- 72 a^4 b^5 c^8}{- 9 a^2 b^2 c^3}\]
\[ = \frac{- 72 \times a \times a \times a \times a \times b \times b \times b \times b \times b \times c \times c \times c \times c \times c \times c \times c \times c}{- 9 \times a \times a \times b \times b \times c \times c \times c}\]
\[ = 8 a^{(4 - 2)} b^{(5 - 2)} c^{(8 - 3)} \]
\[ = 8 a^2 b^3 c^5\]
RELATED QUESTIONS
Which of the following expressions are not polynomials?
Divide 24a3b3 by −8ab.
Divide \[y^4 - 3 y^3 + \frac{1}{2} y^2 by 3y\]
Divide 4z3 + 6z2 − z by −\[\frac{1}{2}\]
Divide x2 + 7x + 12 by x + 4.
Divide 3x3 + 4x2 + 5x + 18 by x + 2.
Find whether the first polynomial is a factor of the second.
x + 1, 2x2 + 5x + 4
Divide: 15a3b4 − 10a4b3 − 25a3b6 by −5a3b2
8x3y ÷ 4x2 = 2xy
The denominator of a fraction exceeds Its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, we get `3/2`. Find the original fraction.
