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Divide: (28"A"^2"B"^3)/"C"^2 by 4abc

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Question

Divide:

`(28"a"^2"b"^3)/"c"^2` by 4abc

Sum
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Solution

`(28"a"^2"b"^3)/"c"^2÷4"abc"`

= `(4xx7xx"a"^(2-1)xx"b"^(3-1))/(4xx"c"^(2+1))`

= `(7"ab"^2)/"c"^3`

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Chapter 14: Fundamental Concepts (Including Angles and their Properties) - Exercise 19 (D)

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Selina Concise Mathematics [English] Class 6 ICSE
Chapter 14 Fundamental Concepts (Including Angles and their Properties)
Exercise 19 (D) | Q 3.6
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