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Question
Divide 216 into three parts which are in A.P. and the product of two smaller parts is 5040.
Sum
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Solution
Let the three parts of 216 in A.P. be (a – d), a, (a + d).
`\implies` a – d + a + a + d = 216
`\implies` 3a = 216
`\implies` a = 72
Given that the product of two smaller parts is 5040.
`\implies` a(a – d) = 5040
`\implies` 72(72 – d) = 5040
`\implies` 72 – d = 70
`\implies` d = 2
∴ a – d = 72 – 2 = 70, a = 72 and a + d = 72 + 2 = 74
Therefore, the three parts of 216 are 70, 72 and 74.
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