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Div » P a Mars Satellite Moving in an Orbit of Radius 9.4 × 103 Km Takes 27540 S to Complete One Revolution. Calculate the Mass of Mars. - Physics

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Question

A Mars satellite moving in an orbit of radius 9.4 × 103 km takes 27540 s to complete one revolution. Calculate the mass of Mars.

Sum
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Solution

Time period of revolution of the satellite around the Mars is give by  \[T = 2\pi\sqrt{\frac{r^3}{GM}}\] where M is the mass of the Mars and r is the distance of the satellite from the centre of the planet.

\[\text { Now }, 27540 = 2 \times 3 . 14\sqrt{\frac{\left( 9 . 4 \times {10}^3 \times {10}^3 \right)^3}{6 . 67 \times {10}^{- 11} \times M}}\]

\[ \Rightarrow \left( 27540 \right)^2 = \left( 6 . 28 \right)^2 \times \frac{\left( 9 . 4 \times {10}^5 \right)^3}{6 . 67 \times {10}^{- 11} \times M}\]

\[ \Rightarrow M = \frac{\left( 6 . 28 \right)^2 \times \left( 9 . 4 \right)^3 \times {10}^{18}}{6 . 67 \times {10}^{- 11} \times \left( 27540 \right)^2}\]

\[ \Rightarrow M = 6 . 5 \times {10}^{23} kg\]

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Chapter 11: Gravitation - Exercise [Page 227]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 11 Gravitation
Exercise | Q 31 | Page 227

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