Question

Differentiate \[x^{\sin^{- 1} x}\]  ?

Answer 1

\[\text{ Let y } = x^{\sin^{- 1} x} . . . \left( i \right)\]
\[\text{ Taking log on both sides }, \]
\[\log y = \log x^{\sin^{- 1} x } \]
\[ \Rightarrow \log y = \sin^{- 1} x \log x \]
\[\text{ Differentiating with respect to x }, \]
\[\frac{1}{y}\frac{dy}{dx} = \sin^{- 1} x\frac{d}{dx}\left( \log x \right) + \left( \log x \right)\frac{d}{dx}\left( \sin^{- 1} x \right) \]
\[ \Rightarrow \frac{1}{y}\frac{dy}{dx} = \sin^{- 1} x\left( \frac{1}{x} \right) + \left( \log x \right)\left( \frac{1}{\sqrt{1 - x^2}} \right)\]
\[ \Rightarrow \frac{dy}{dx} = y\left[ \frac{\sin^{- 1} x}{x} + \frac{\log x}{\sqrt{1 - x^2}} \right]\]
\[ \Rightarrow \frac{dy}{dx} = x^{\sin^{- 1} x} \left[ \frac{\sin^{- 1} x}{x} + \frac{\log x}{\sqrt{1 - x^2}} \right] \left[ \text{ using equation } \left( i \right) \right]\]