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Question
Differentiate the following:
y = (x2 + 4x + 6)5
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Solution
Let = u = x2 + 4x + 6
⇒ `("d"u)/("d"x)` = 2x + 4
Now y = u5
⇒ `("d"y)/("d"x)` = 5u4
∴ `("d"y)/("d"x) = ("d"y)/("d"x) xx ("d"u)/("d"x)` = 5u4 (2x + 4)
= 5(x2 + 4x + 6)4 (2x + 4)
= 5(2x + 4) (x2 + 4x + 6)4
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