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Question
Differentiate the following w.r.t.x. :
y = ex logx
Sum
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Solution
y = ex logx
∴ `("d"y)/("d"x) = "d"/("d"x)["e"^x log x]`
= `"e"^x "d"/("d"x) (log x) + (log x)"d"/("d"x) ("e"^x)`
= `"e"^x (1/x) + (log x)("e"^x)`
= `"e"^x (1/x + log x)`.
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Derivative of Logarithmic Functions
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