Question

Differentiate the following w. r. t. x. : x³ .3^x

Answer 1

Let y = x³ 3^x
Differentiating w.r.t. x, we get

`dy/dx = d/dx (x^3 3^x)`

= `x^3d/dx(3^x) + 3^x d/dx(x^3)`

= (x³)(3^x log 3) + 3^x(3x²)

= x² 3^x (xlog3 + 3)