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Differentiate log (1 + x2) with respect to ax. - Mathematics and Statistics

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Question

Differentiate log (1 + x2) with respect to ax.

Sum
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Solution

Let u = log (1 + x2) and v = ax

u = log (1 + x2)

Differentiating both sides w.r.t.x, we get

`"du"/"dx" = 1/(1 + "x"^2) * "d"/"dx" (1 + "x"^2)`

`= 1/(1 + "x"^2) * (0 + "2x")`

∴ `"du"/"dx" = "2x"/(1 + "x"^2)`

v = a

Differentiating both sides w.r.t.x, we get

`"dv"/"dx" = "a"^"x" * log "a"`

∴ `"du"/"dv" = ("du"/"dx")/("dv"/"dx") = ("2x"/(1 + "x"^2))/("a"^"x" * log "a")`

∴ `"du"/"dv" = "2x"/("a"^"x" * log "a" * (1 + "x"^2))`

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The Concept of Derivative - Derivatives of Logarithmic Functions
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Chapter 3: Differentiation - MISCELLANEOUS EXERCISE - 3 [Page 100]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 3 Differentiation
MISCELLANEOUS EXERCISE - 3 | Q IV] 17) | Page 100

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