Question

If y = e^logx then `dy/dx` = ?

Options

• `(e^(logx))/x`

• `1/x`

• 0

• `1/2`

Answer 1

`(e^(log x))/x`

Explanation:

y = e^logx

Differentiating both sides w.r.t.x, we get

`dy/dx = e^(logx).d/dx`(logx)

= `e^(logx).1/x`

= `(e^(logx))/x`