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Question
Differentiate e4x + 5 w.r..t.e3x
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Solution
Let u = e4x + 5 and v = e3x
`(du)/dx = 4e^(4x + 5) and (dv)/dx = 3e^(3x)`
we have to find `(du)/(dv)`
`(du)/(dv) = ((du)/(dx))/((dv)/(dx)) = [4e^(4x + 5)]/[3e^(3x)]`
= `4/3e^( 4x + 5 - 3x)`
= `4/3e^( x + 5 )`
`therefore (du)/(dv) = 4/3e^( x + 5 )`
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