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Diagram alongside shows a glass slab, such that a ray of light AB is incident on it at an angle of near 90°. If the critical angle for glass is 42°, trace the course of ray AB, through glass

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Question

Diagram alongside shows a glass slab, such that a ray of light AB is incident on it at an angle of near 90°. If the critical angle for glass is 42°, trace the course of ray AB, through glass, till it emerges out in air. Copy the diagram.

Diagram
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Solution

Ray AB strikes the face at B at nearly 90° (grazing incidence), so it refracts into the glass at an angle of 42°, equal to the critical angle.

The two faces of the slab are parallel, so the refracted ray BC meets the lower face at C at 42°, which again equals the critical angle.

Since the angle of incidence at C equals the critical angle, the angle of refraction there is 90°. The ray CD therefore leaves the slab grazing along its lower surface.

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Chapter 4: Refraction of Light - EXERCISE-2 [Page 82]

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Goyal Brothers Prakashan A New Approach to ICSE Physics [English] Class 10
Chapter 4 Refraction of Light
EXERCISE-2 | Q 5. | Page 82
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