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Question
Determine the region in the plane determined by the inequalities:
2x + 3y ≤ 35, y ≥ 2, x ≥ 5.
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Solution
If 2x + 3y = 35 then
| x | 1 | 10 |
| y | 11 | 5 |
y = 2 is a line parallel to X-axis at a distance 2 units
x = 5 is a line parallel to Y-axis at a distance of 5 units
The required region is below 2x + 3y = 35, above y = 2 and to the right of x = 5
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