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Question
Determine the AP whose fifth term is 19 and the difference of the eighth term from the thirteenth term is 20.
Sum
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Solution
We know that,
The first term of an AP = a
And the common difference = d
According to the question,
5th term, a5 = 19
Using the nth term formula,
an = a + (n – 1)d
We get,
a + 4d = 19
a = 19 – 4d ...(1)
Also,
13th term – 8th term = 20
a + 12d – (a + 7d) = 20
5d = 20
d = 4
Substituting d = 4 in equation 1,
We get,
a = 19 – 4(4)
a = 3
Then, the AP becomes,
3, 3 + 4, 3 + 2(4),...
3, 7, 11,...
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