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Question
Describe the effect of Removal of CO on the equilibrium of the reaction:
\[\ce{2H2(g) + CO (g) ⇌ CH3OH (g)}\]
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Solution
On removing CO, the equilibrium will shift in the backward direction.
RELATED QUESTIONS
For the following equilibrium, Kc = 6.3 × 1014 at 1000 K
\[\ce{NO (g) + O3 (g) ⇌ NO2 (g) + O2 (g)}\]
Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?
Describe the effect of addition of H2 on the equilibrium of the reaction:
\[\ce{2H2(g) + CO (g) ⇌ CH3OH (g)}\]
Describe the effect of Addition of CH3OH on the equilibrium of the reaction:
\[\ce{2H2(g) + CO (g) ⇌ CH3OH (g)}\]
Describe the effect of Removal of CH3OH on the equilibrium of the reaction:
\[\ce{2H2(g) + CO (g) ⇌ CH3OH (g)}\]
Dihydrogen gas used in Haber’s process is produced by reacting methane from natural gas with high-temperature steam. The first stage of two-stage reaction involves the formation of CO and H2. In the second stage, CO formed in the first stage is reacted with more steam in water gas shift reaction,
\[\ce{CO (g) + H2O (g) ⇌ CO2 (g) + H2 (g)}\]
If a reaction vessel at 400°C is charged with an equimolar mixture of CO and steam such that `"p"_"CO" = "p"_("H"_2"O")` = 4.0 bar, what will be the partial pressure of H2 at equilibrium? Kp = 10.1 at 400°C.
Which of the following is NOT a general characteristic of equilibria involving physical processes?
