Advertisements
Advertisements
Question
`"d"/"dx"` (5ex – 2 log x) is equal to:
Options
`5e^x - 2/x`
5ex - 2x
`5e^x - 1/x`
2 log x
Advertisements
Solution
`5e^x - 2/x`
APPEARS IN
RELATED QUESTIONS
Evaluate the following:
\[\lim_{x->∞} \frac{2x + 5}{x^2 + 3x + 9}\]
Evaluate the following:
`lim_(x->∞) (sum "n")/"n"^2`
Evaluate the following:
`lim_(x->0) (sin^2 3x)/x^2`
Let f(x) = `("a"x + "b")/("x + 1")`, if `lim_(x->0) f(x) = 2` and `lim_(x->∞) f(x) = 1`, then show that f(-2) = 0
Find the derivative of the following function from the first principle.
log(x + 1)
If f(x)= `{((x - |x|)/x if x ≠ 0),(2 if x = 0):}` then show that `lim_(x->1)`f(x) does not exist.
Evaluate: `lim_(x->1) ((2x - 3)(sqrtx - 1))/(2x^2 + x - 3)`
\[\lim_{x->0} \frac{e^x - 1}{x}\]=
A function f(x) is continuous at x = a `lim_(x->"a")`f(x) is equal to:
If y = x and z = `1/x` then `"dy"/"dx"` =
