Advertisements
Advertisements
Question
`"d"/"dx" (1/x)` is equal to:
Options
-\[\frac{1}{x^2}\]
-\[\frac{1}{x}\]
log x
\[\frac{1}{x^2}\]
Advertisements
Solution
-\[\frac{1}{x^2}\]
APPEARS IN
RELATED QUESTIONS
Evaluate the following:
`lim_(x->a) (x^(5/8) - a^(5/8))/(x^(2/3) - a^(2/3))`
If `lim_(x->a) (x^9 + "a"^9)/(x + "a") = lim_(x->3)` (x + 6), find the value of a.
If `lim_(x->2) (x^n - 2^n)/(x-2) = 448`, then find the least positive integer n.
Examine the following function for continuity at the indicated point.
f(x) = `{((x^2 - 9)/(x-3) "," if x ≠ 3),(6 "," if x = 3):}` at x = 3
Show that f(x) = |x| is continuous at x = 0.
If f(x) = `{(x^2 - 4x if x >= 2),(x+2 if x < 2):}`, then f(0) is
A function f(x) is continuous at x = a `lim_(x->"a")`f(x) is equal to:
`"d"/"dx"` (5ex – 2 log x) is equal to:
If y = x and z = `1/x` then `"dy"/"dx"` =
If y = e2x then `("d"^2"y")/"dx"^2` at x = 0 is:
