Advertisements
Advertisements
Question
`"d"/"dx" (1/x)` is equal to:
Options
-\[\frac{1}{x^2}\]
-\[\frac{1}{x}\]
log x
\[\frac{1}{x^2}\]
Advertisements
Solution
-\[\frac{1}{x^2}\]
APPEARS IN
RELATED QUESTIONS
Evaluate the following:
`lim_(x->0) (sqrt(1+x) - sqrt(1-x))/x`
Evaluate the following:
`lim_(x->a) (x^(5/8) - a^(5/8))/(x^(2/3) - a^(2/3))`
If `lim_(x->a) (x^9 + "a"^9)/(x + "a") = lim_(x->3)` (x + 6), find the value of a.
If f(x) = `(x^7 - 128)/(x^5 - 32)`, then find `lim_(x-> 2)` f(x)
Let f(x) = `("a"x + "b")/("x + 1")`, if `lim_(x->0) f(x) = 2` and `lim_(x->∞) f(x) = 1`, then show that f(-2) = 0
Examine the following function for continuity at the indicated point.
f(x) = `{((x^2 - 9)/(x-3) "," if x ≠ 3),(6 "," if x = 3):}` at x = 3
Show that the function f(x) = 2x - |x| is continuous at x = 0
If y = e2x then `("d"^2"y")/"dx"^2` at x = 0 is:
If y = log x then y2 =
`"d"/"dx" ("a"^x)` =
