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Critical angle for total internal reflection from a medium to a vacuum is 60°. Find the velocity of light in the given medium. - Physics (Theory)

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Question

Critical angle for total internal reflection from a medium to a vacuum is 60°. Find the velocity of light in the given medium.

Numerical
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Solution

Given:

Critical angle, C = 60°

Velocity of light in vacuum, c = 3 × 108 m/s

Step 1: Use the formula for critical angle:

sin C = `1/μ`

μ = `1/(sin C)`

= 1/(sin 60°)

= `1/((sqrt3)/2)`

≈ `1/0.866`

≈ 1.1547

Step 2: Use refractive index to find velocity:

μ = `c/v`

v = `c/μ`

= `(3 xx 10^8)/1.1547`

≈ 2.6 × 108 m/s

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Chapter 15: Refraction of Light at a Plane Interface : Total Internal Reflection : Optical Fibre - QUESTIONS [Page 783]

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Nootan Physics Part 1 and 2 [English] Class 12 ISC
Chapter 15 Refraction of Light at a Plane Interface : Total Internal Reflection : Optical Fibre
QUESTIONS | Q 14. | Page 783
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