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A ray of light falls normally on the face of a glass prism (n = 1.5). Find the angle of the prism if the ray just fails to emerge from the second face. - Physics (Theory)

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Question

A ray of light falls normally on the face of a glass prism (n = 1.5). Find the angle of the prism if the ray just fails to emerge from the second face.

Numerical
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Solution

Given:

Refractive index of glass, n = 1.5

Ray falls normally on the first face (so it goes undeviated)

The ray just fails to emerge from the second face (i.e., total internal reflection occurs).

To Find:

Angle of the prism A

Concept used:

When a ray falls normally on one face and just fails to emerge from the second face, the angle of incidence at the second face equals the critical angle.

From prism geometry:

Angle of incidence at second face = A

At the point of total internal reflection:

A = C (critical angle)

Calculation:

Now, using the formula:

sin C = `1/n`

sin C = `1/1.5`

sin C = 0.6667

C = sin−1 (0.6667)

C ≈ 41.8°

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Chapter 15: Refraction of Light at a Plane Interface : Total Internal Reflection : Optical Fibre - QUESTIONS [Page 783]

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Nootan Physics Part 1 and 2 [English] Class 12 ISC
Chapter 15 Refraction of Light at a Plane Interface : Total Internal Reflection : Optical Fibre
QUESTIONS | Q 15. | Page 783
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