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Question
\[\ce{Cr2O^{2-}_7 + 14H+ + 6e- -> 2}\]______ + 7H2O
Fill in the Blanks
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Solution
\[\ce{Cr2O^{2-}_7 + 14H+ + 6e- -> 2\mathbf{\underline{Cr^{3+}}}}\] + 7H2O
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