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Question
`(cos 80^circ)/(sin 10^circ) + cos 59^circ "cosec" 31` = ______.
Fill in the Blanks
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Solution
`(cos 80^circ)/(sin 10^circ) + cos 59^circ "cosec" 31` = 2.
Explanation:
`(cos 80^circ)/(sin 10^circ) + cos 59^circ "cosec" 31^circ`
= `(cos(90^circ - 10^circ))/(sin 10^circ) + cos(90^circ - 31^circ) xx 1/(sin 31^circ)`
= `(sin 10^circ)/(sin 10^circ) + sin 31^circ xx 1/(sin 31^circ)`
= 1 + 1
= 2
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