Question

Copy and complete the nuclear reaction by filling in the blanks.

\[ {}_{92}\mathrm{U}^{235} + {}_{0}\mathrm{n}^{1} \longrightarrow {}_{56}\mathrm{Ba}^{\cdots\cdots} + {}_{\cdots\cdots}\mathrm{Kr}^{92} + 3\,{}_{0}\mathrm{n}^{1} \]

Answer 1

\[\ce{_92U^235 + _0n^1 -> _56Ba^{141} + _{36}Kr^92 + 3 _0n^1}\]

Answer 2

\[ {{}^{235}_{92}\mathrm{U}+{}^{1}_{0}\mathrm{n}\longrightarrow{}^{141}_{56}\mathrm{Ba}+{}^{92}_{36}\mathrm{Kr}+3\,{}^{1}_{0}\mathrm{n}} \]