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Question
Convert given fraction into a fraction with equal numerators:
`15/19, 25/28, 9/11 "and" 45/47`
Sum
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Solution
In `15/19, 25/28, 9/11 "and" 45/47`,
L.C.M. of 15, 25, 9 and 45 = 225
`therefore 15/19 = (15 xx 15)/(19 xx 15) = 225/285`
`25/28 = (25 xx 9)/(28 xx 9) = 225/252`
`9/11 = (9 xx 25)/(11 xx 25) = 225/275`
and `45/47 = (45 xx 5)/(47 xx 5) = 225/235`
Hence the required fractions are `225/285, 225/252, 225/275 "and" 225/235`
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