Advertisements
Advertisements
Question
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.
Advertisements
Solution
The below given steps will be followed to construct the required triangle.
Step I:- Draw a line segment AB of 11 cm.
(As XY + YZ + ZX = 11 cm)
Step II:- Construct an angle, ∠PAB, of 30° at point A and an angle, ∠QBA, of 90° at point B.
Step III:- Bisect ∠PAB and ∠QBA. Let these bisectors intersect each other at point X.
Step IV:- Draw perpendicular bisector ST of AX and UV of BX.
Step V:- Let ST intersect AB at Y and UV intersect AB at Z.
Join XY, XZ.
ΔXYZ is the required triangle.

RELATED QUESTIONS
Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.
Construct a ΔABC in which BC = 3.4 cm, AB − AC = 1.5 cm and ∠B = 45°.
Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.
Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11.
The construction of a triangle ABC, given that BC = 3 cm, ∠C = 60° is possible when difference of AB and AC is equal to ______.
A triangle ABC can be constructed in which AB = 5 cm, ∠A = 45° and BC + AC = 5 cm.
A triangle ABC can be constructed in which ∠B = 60°, ∠C = 45° and AB + BC + AC = 12 cm.
Construct the following and give justification:
A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm.
Construct the following and give justification:
An equilateral triangle if its altitude is 3.2 cm.
Construct the following and give justification:
A rhombus whose diagonals are 4 cm and 6 cm in lengths.
