Question

Construct a trapezium ABCD where AB || CD, AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.

[Hint: Difference of two parallel sides gives an equilateral triangle.]

Answer 1

Steps of construction:

Step I: Draw a line segment DC = 9.6 cm.

Step II: With D as centre, draw an angle measure 60°. Now, cut-off it with an arc 3.2 cm called point A.

Step III: Now, draw a parallel AB || CD.

Step IV: Talking C as centre, cut an arc B measure 3.2 cm on previous parallel line.

Step V: Draw a line segment BE = 3.2 cm from arc B.

Step VI: Join B to E and C.

Hence, ABCD is a required trapezium where ∠A = 120° and ∠B = 60°.