Advertisements
Advertisements
Question
Construct a trapezium ABCD where AB || CD, AD = BC = 3.2 cm, AB = 6.4 cm and CD = 9.6 cm. Measure ∠B and ∠A.
[Hint: Difference of two parallel sides gives an equilateral triangle.]
Advertisements
Solution
Steps of construction:
Step I: Draw a line segment DC = 9.6 cm.
Step II: With D as centre, draw an angle measure 60°. Now, cut-off it with an arc 3.2 cm called point A.
Step III: Now, draw a parallel AB || CD.
Step IV: Talking C as centre, cut an arc B measure 3.2 cm on previous parallel line.
Step V: Draw a line segment BE = 3.2 cm from arc B.
Step VI: Join B to E and C.
Hence, ABCD is a required trapezium where ∠A = 120° and ∠B = 60°.
APPEARS IN
RELATED QUESTIONS
All parallelograms are trapeziums.
All squares are trapeziums.
Which of the following figures satisfy the following property?
- Only one pair of sides are parallel.
A quadrilateral in which a pair of opposite sides is parallel is ______.
In trapezium ABCD with AB || CD, if ∠A = 100°, then ∠D = ______.
Every rhombus is a trapezium.
Of the four quadrilaterals-square, rectangle, rhombus and trapezium-one is somewhat different from the others because of its design. Find it and give justification.
In trapezium HARE, EP and RP are bisectors of ∠E and ∠R respectively. Find ∠HAR and ∠EHA.
Construct a trapezium ABCD in which AB || DC, ∠A = 105°, AD = 3 cm, AB = 4 cm and CD = 8 cm.
Construct a trapezium RISK in which RI || KS, RI = 7 cm, IS = 5 cm, RK = 6.5 cm and ∠I = 60°.
