Advertisements
Advertisements
Question
Construct a ∆ ABC such that:
AB = 7 cm, BC = 5 cm and ∠ABC = 60°
Advertisements
Solution
Steps of Construction :
(i) Draw a line segment AB = 7 cm.

(ii) At B, draw a ray making an angle of 60° and cut off BC = 5 cm
(iii) Join AC.
∆ ABC is the required triangle.
APPEARS IN
RELATED QUESTIONS
Construct a ∆ABC such that:
AB = 6 cm, BC = 4 cm and CA = 5.5 cm
Construct a ∆ PQR such that :
PQ = 6 cm, ∠Q = 60° and ∠P = 45°. Measure ∠R.
Construct an isosceles Δ ABC such that:
Base BC = 4 cm and base angle = 30°. Measure the other two sides of the triangle.
Construct an isosceles Δ ABC such that:
Base AC = 5 cm and base angle = 75°. Measure the other two sides of the triangle.
Construct an isosceles ∆ ABC such that:
AB = AC = 6.5 cm and ∠A = 60°
Construct an isosceles ∆ ABC such that:
One of the equal sides = 6 cm and vertex angle = 45°. Measure the base angles.
Construct an isosceles ∆ ABC such that:
BC = AB = 5.8 cm and ZB = 30°. Measure ∠A and ∠C.
Construct an equilateral Δ ABC such that:
AB = 5 cm. Draw the perpendicular bisectors of BC and AC. Let P be the point of intersection of these two bisectors. Measure PA, PB, and PC.
Construct an isosceles ∆ MNP such that base MN = 5.8 cm, base angle MNP = 30°. Construct an incircle to this triangle and measure its radius.
Construct a ∆ PQR such that PQ = 6 cm, ∠QPR = 45° and angle PQR = 60°. Locate its incentre and then draw its incircle.
