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Question
Construct a ΔABC in which BC = 5 cm, ∠C = 60° and altitude from A equal to 3 cm. Construct a ΔADE similar to ΔABC such that each side of ΔADE is `3/2` times the corresponding side of ΔABC. Write the steps of construction.
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Solution
Steps of Construction:
Step 1: Draw a line l.
Step 2: Draw an angle of 90° at M on l.
Step 3: Cut an arc of radius 3 cm on the perpendicular. Mark the point as A.
Step 4: With A as centre, make an angle of 30° and let it cut l at C. We get ∠ACB = 60°.
Step 5: Cut an arc of 5 cm from C on l and mark the point as B.
Step 6: Join AB. Thus, ΔABC is obtained.
Step 7: Extend AB to D, such that BD = BC.
Step 8: Draw DE || BC, cutting AC produced to E.

Then, ΔADE is the required triangle, each of whose sides is of the corresponding sides of ΔABC.
