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Question
Consider the following reaction
\[\ce{A <-[Br2 - H2O] Glucose ->[HNO3] B}\]
Here, 'A' and 'B' are respectively.
Options
glucose oxime and saccharic acid
gluconic acid and saccharic acid
saccharic acid and sorbitol
gluconic acid and sorbitol
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Solution
gluconic acid and saccharic acid
Explanation:
\[\begin{array}{cc}
\ce{COOH}\phantom{............}\ce{CHO}\phantom{...........}\ce{COOH}\phantom{..}\\
|\phantom{..................}|\phantom{................}|\phantom{......}\\
\ce{(CHOH)4 <-[Br2 - H2O] (CHOH)4 ->[HNO3] (CHOH)4}\\
|\phantom{..................}|\phantom{................}|\phantom{......}\\
\ce{\underset{acid}{\underset{Gluconic}{CH2OH}}}\phantom{...........}\ce{\underset{Glucose}{CH2OH}}\phantom{.........}\ce{\underset{acid}{\underset{Saccharic}{COOH}}}\end{array}\]
