Question

Consider the following frequency distribution:

Class	0 – 6	6 – 12	12 – 18	18 – 24	24 – 30
Frequency	12	10	15	8	11

The median class is:

Options

• 6 – 12

• 12 – 18

• 18 – 24

• 24 – 30

Answer 1

12 – 18

Explanation:

We have,

`\implies` N = 56

`\implies` N/2 = 28

Cumulative frequency just greater than or equal to 28 lies in interval 12 – 18

So, Median class is 12 – 18