Question

Consider the following frequency distribution:

Class	0 – 5	6 – 11	12 – 17	18 – 23	24 – 29
Frequency	13	10	15	8	11

The upper limit of the median class is ______.

Options

• 16.5

• 18.5

• 18

• 17.5

Answer 1

The upper limit of the median class is 17.5.

Explanation:

Total frequency N = 13 + 10 + 15 + 8 + 11 = 57, so `N/2 = 28.5`.

Cumulative frequencies: 13, 23, 38, 46, 57. The first cumulative ≥ 28.5 is 38, so the median class is 12 – 17.

For grouped (integer) data the class upper boundary = upper class limit + 0.5 → 17 + 0.5 = 17.5.

Therefore the upper limit of the median class is 17.5.