Question

Complete the following fission reaction:

\[\ce{_92U^235 _0n^1 -> _aSb^133 + _41Co^b + 4_0n_1 + energy}\]

Write down the values of a and b.

Answer 1

\[\ce{_92U^235 _0n^1 -> _aSb^133 + _41Co^b + 4_0n_1}\]

Hence, 235 + 1 = 133 + b + 4

or 236 = b + 137

∴ b = 236 - 137 = 99

Similarly 92 = a - 41

∴ a = 92 - 41 = 51

Hence, \[\ce{_92U^235 _0n^1 -> _aSb^133 + _41Co^b + 4_0n_1}\]