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Maharashtra State BoardSSC (English Medium) 10th Standard

Complete the following. 2x + y + 8 2y I am a rectangle. - Algebra Mathematics 1

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Question

Complete the following.

Sum
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Solution

The length of the given rectangle is 2x + y + 8 and 4x - y

2x + y + 8 = 4x - y

⇒ y + y + 8 = 4x - 2x

⇒ 8 + 2y = 2x

⇒ 2x - 2y = 8

Dividing by 2

⇒ x - y = 4     ...(I)

The breadth of the rectangle is 2y and x + 4. 

2y = x + 4

⇒ x - 2y = -4     ...(II)

Subtracting (II) from (I) 

x - x - y - (-2y) = 4 - (-4)

⇒ -y + 2y = 8

⇒ y = 8

Putting the value of y = 8 in (I) we get

x - 8 = 4

⇒ x = 4 + 8 = 12

Length = 4x - y

= 4 × 12 - 8

= 40

Breadth = 2 × 8

= 16

Perimeter = 2 (length + breadth)

= 2 (40 + 16) 

= 112

Area = length × breadth

= 40 × 16

= 640 sq. units

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Chapter 1: Linear Equations in Two Variables - Practice Set 1.5 [Page 26]

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Balbharati Algebra (Mathematics 1) [English] Standard 10 Maharashtra State Board
Chapter 1 Linear Equations in Two Variables
Practice Set 1.5 | Q 2 | Page 26
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