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ClX2+HX2S⟶2HCl+S In the above reaction, oxidation state of sulphur changes from ____________.

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Question

\[\ce{Cl2 + H2S -> 2HCl + S}\]

In the above reaction, oxidation state of sulphur changes from ____________.

Options

  • zero to −2

  • −2 to zero

  • zero to +2

  • +2 to zero

MCQ
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Solution

\[\ce{Cl2 + H2S -> 2HCl + S}\]

In the above reaction, oxidation state of sulphur changes from −2 to zero.

Explanation:

\[\ce{Cl2 + H2\overset{-2}{S} -> 2HCl + \overset{0}{S}}\]

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