English

Choose the correct options from the given alternatives : 2∫cos2x-sin2xcos2x+sin2x⋅dx =

Advertisements
Advertisements

Question

Choose the correct options from the given alternatives :

`2 int (cos^2x - sin^2x)/(cos^2x + sin^2x)*dx` =

Options

  • sin 2x + c

  • cos 2x + c

  • tan 2x + c

  • 2 sin 2x + c

MCQ
Advertisements

Solution

sin 2x + c

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Indefinite Integration - Miscellaneous Exercise 3 [Page 149]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Indefinite Integration
Miscellaneous Exercise 3 | Q 1.15 | Page 149

RELATED QUESTIONS

Evaluate : `int_0^pi(x)/(a^2cos^2x+b^2sin^2x)dx`


Evaluate :

`int(sqrt(cotx)+sqrt(tanx))dx`


Integrate the functions:

`cos sqrt(x)/sqrtx`


Integrate the functions:

`(sin x)/(1+ cos x)^2`


Integrate the functions:

`sqrt(tanx)/(sinxcos x)`


\[\int\sqrt{3 + 2x - x^2} \text{ dx}\]

\[\int\sqrt{x - x^2} dx\]

\[\int e^x \sqrt{e^{2x} + 1} \text{ dx}\]

Write a value of\[\int\frac{\sin x - \cos x}{\sqrt{1 + \sin 2x}} \text{ dx}\]


Write a value of\[\int\sqrt{4 - x^2} \text{ dx }\]


Evaluate:  \[\int\frac{x^3 - 1}{x^2} \text{ dx}\]


\[If \int e^x \left( \tan x + 1 \right)\text{ sec  x  dx } = e^x f\left( x \right) + C, \text{ then  write  the value  of  f}\left( x \right) .\]

 

 


 Show that : `int _0^(pi/4) "log" (1+"tan""x")"dx" = pi /8 "log"2`


Integrate the following w.r.t. x : `(3x^3 - 2x + 5)/(xsqrt(x)`


Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


Evaluate the following integrals : `int (3)/(sqrt(7x - 2) - sqrt(7x - 5)).dx`


Integrate the following functions w.r.t. x : e3logx(x4 + 1)–1 


Integrate the following functions w.r.t.x:

`(2sinx cosx)/(3cos^2x + 4sin^2 x)`


Evaluate the following : `int (1)/sqrt(8 - 3x + 2x^2).dx`


Evaluate the following integral:

`int (3cosx)/(4sin^2x + 4sinx - 1).dx`


Evaluate the following.

`int 1/(sqrt"x" + "x")` dx


Evaluate the following.

`int 1/(4"x"^2 - 1)` dx


Fill in the Blank.

`int 1/"x"^3 [log "x"^"x"]^2 "dx" = "P" (log "x")^3` + c, then P = _______


`int cos sqrtx` dx = _____________


`int (2(cos^2 x - sin^2 x))/(cos^2 x + sin^2 x)` dx = ______________


`int 1/(xsin^2(logx))  "d"x`


`int x/(x + 2)  "d"x`


To find the value of `int ((1 + logx))/x` dx the proper substitution is ______


`int (1 + x)/(x + "e"^(-x))  "d"x`


`int(5x + 2)/(3x - 4) dx` = ______


`int (cos x)/(1 - sin x) "dx" =` ______.


`int(3x + 1)/(2x^2 - 2x + 3)dx` equals ______.


If `int sinx/(sin^3x + cos^3x)dx = α log_e |1 + tan x| + β log_e |1 - tan x + tan^2x| + γ tan^-1 ((2tanx - 1)/sqrt(3)) + C`, when C is constant of integration, then the value of 18(α + β + γ2) is ______.


The value of `int (sinx + cosx)/sqrt(1 - sin2x) dx` is equal to ______.


The value of `sqrt(2) int (sinx  dx)/(sin(x - π/4))` is ______.


Evaluate `int_(logsqrt(2))^(logsqrt(3)) 1/((e^x + e^-x)(e^x - e^-x)) dx`.


Find : `int sqrt(x/(1 - x^3))dx; x ∈ (0, 1)`.


Evaluate the following.

`int 1/(x^2 + 4x - 5)dx`


Evaluate `int (1)/(x(x - 1))dx`


Evaluate the following.

`int x^3 e^(x^2) dx`


The value of `int ("d"x)/(sqrt(1 - x))` is ______.


Evaluate `int(1+x+(x^2)/(2!))dx`


Evaluate the following.

`intx^3/sqrt(1+x^4)dx`


Evaluate the following.

`int1/(x^2+4x-5)dx`


Evaluate `int (1 + x + x^2/(2!)) dx`


Evaluate the following:

`int x^3/(sqrt(1 + x^4)) dx`


Evaluate the following.

`int1/(x^2 + 4x - 5)dx`


Which standard substitution is used for \[\sqrt{x^2-a^2}\], \[\frac{1}{\sqrt{x^2-a^2}}\], or \[x^2-a^2\]?


For indefinite integrals, what should be done after integration in the new variable?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×