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Question
Choose the correct alternative:
The value of `1/(2!) + 1/(4!) + 1/(6!) + ...` is
Options
`("e"^2 + 1)/(2"e")`
`("e" + 1)^2/(2"e")`
`("e" - 1)^2/(2"e")`
`("e"^2 - 1)/(2"e")`
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Solution
`("e" - 1)^2/(2"e")`
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