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Choose the correct alternative. If xyx + ym + 1x4.y5=(x + y)m + 1 then dydxyxdydx=yx then m = ? - Mathematics and Statistics

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Question

Choose the correct alternative.

If `"x"^4."y"^5 = ("x + y")^("m + 1")` then `"dy"/"dx" = "y"/"x"` then m = ?

Options

  • 8

  • 4

  • 5

  • 20

MCQ
Sum
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Solution

8

Explanation:

x4. y5 = (x + y)m + 1           ...(i)

∴ `"d"/"dx" ("x"^4. "y"^5) = "d"/"dx" ("x" + "y")^("m" + 1)`

∴ `"x"^4 "d"/"dx" "y"^5 + "y"^5 "d"/"dx" "x"^4 = ("m" + 1)("x" + "y")^("m" + 1 − 1) . "d"/"dx" ("x" + "y")`

∴ `"x"^4 . 5"y"^4  "d"/"dx" "y"+ "y"^5  4"x"^3 "d"/"dx" "x" = ("m" + 1)("x" + "y")^"m" ["d"/"dx" "x" + "d"/"dx" "y"]`

∴ `5"x"^4"y"^4 "dy"/"dx" + 4"x"^3 "y"^5 . 1 = ("m" + 1)("x" + "y")^"m" [1 + "dy"/"dx"]`

∴ `5"x"^4"y"^4 "dy"/"dx" + 4"x"^3 "y"^5 = ("m" + 1)("x" + "y")^"m" [1 + "dy"/"dx"]`

Put `"dy"/"dx" = "y"/"x"`

∴ `5"x"^((cancel4)3)"y"^4 . "y"/cancel"x" + 4"x"^3 "y"^5 = ("m" + 1)("x" + "y")^"m" [1 + "y"/"x"]`

∴ `5"x"^3"y"^4 . "y" + 4"x"^3 "y"^5 = ("m" + 1)("x" + "y")^"m" [("x" + "y")/"x"]`

∴ `5"x"^3"y"^5 + 4"x"^3 "y"^5 = ("m" + 1)("x" + "y")^"m" [("x" + "y")/"x"]`

∴ `9"x"^3"y"^5 = ("m" + 1)/"x" [("x" + "y")^("m" + 1)]`

∴ `9"x"^3"y"^5 = ("m" + 1)/cancel"x" "x"^((cancel4)3)."y"^5`

∴ `9cancel("x"^3"y"^5) = ("m" + 1) cancel("x"^3"y"^5)`

∴ 9 = m + 1

∴ m = 9 - 1

∴ m = 8

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Chapter 3: Differentiation - MISCELLANEOUS EXERCISE - 3 [Page 99]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 3 Differentiation
MISCELLANEOUS EXERCISE - 3 | Q I] 8) | Page 99

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