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Choose the correct alternative. If ax2 + 2hxy + by2 = 0 then dydx=? - Mathematics and Statistics

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Question

Choose the correct alternative.

If ax2 + 2hxy + by2 = 0 then `"dy"/"dx" = ?` 

Options

  • `(("ax" + "hx"))/(("hx" + "by"))`

  • `(-("ax" + "hx"))/(("hx" + "by"))`

  • `(("ax" - "hx"))/(("hx" + "by"))`

  • `(("2ax" + "hy"))/(("hx" + "3by"))`

MCQ
Sum
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Solution

`(-("ax" + "hx"))/(("hx" + "by"))`

Explanation:

ax2 + 2hxy + by2 = 0

Differentiating both sides w.r.t.x, we get

`"a"(2"x") + "2h" * "d"/"dx" ("xy") + "b"("2y") "dy"/"dx" = 0`

∴ 2ax + 2h `["x" * "dy"/"dx" + "y"(1)] + 2"by" "dy"/"dx" = 0`

∴ 2ax + 2hx `"dy"/"dx"` + 2hy + 2by`"dy"/"dx"` = 0

∴ 2`"dy"/"dx"`(hx + by) = - 2ax - 2hy

∴ 2`"dy"/"dx" = (-2("ax" + "hy"))/(("hx" + "by"))`

∴ `"dy"/"dx" = (-("ax" + "hx"))/(("hx" + "by"))`

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Chapter 3: Differentiation - MISCELLANEOUS EXERCISE - 3 [Page 99]

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Balbharati Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 3 Differentiation
MISCELLANEOUS EXERCISE - 3 | Q I] 7) | Page 99

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