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Question
Choose the correct alternative:
If f(x) = |x − 2| + |x + 2|, x ∈ R, then
Options
f(x) = `{{:(- 2x, "if" x ∈ (- ∞, - 2]),(4, "if" x ∈ (- 2, 2]),(2x, "if" x ∈ (2, ∞)):}`
f(x) = `{{:(2x, "if" x ∈ (- ∞, - 2]),(4x, "if" x ∈ (- 2, 2]),(- 2x, "if" x ∈ (2, ∞)):}`
f(x) = `{{:(- 2x, "if" x ∈ (- ∞, - 2]),(- 4x, "if" x ∈ (- 2, 2]),(2x, "if" x ∈ (2, ∞)):}`
f(x) = `{{:(- 2x, "if" x ∈ (- ∞, - 2]),(2x, "if" x ∈ (- 2, 2]),(2x, "if" x ∈ (2, ∞)):}`
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Solution
f(x) = `{{:(- 2x, "if" x ∈ (- ∞, - 2]),(4, "if" x ∈ (- 2, 2]),(2x, "if" x ∈ (2, ∞)):}`
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