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Question
Cards marked with numbers 1, 2, 3 ......... 20 are well shuffled and a card is drawn at random. What is the probability that the number on the card is divisible by 3?
Sum
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Solution
Total possible outcomes = 20
Favorable outcomes for a number divisible by 3 = 3, 6, 9, 12, 15, 18
Number of favorable outcomes = 6
P(divisible by 3) = `6/20 = 3/10`
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Chapter 25: Probability - Exercise 25 (C) [Page 396]
