Question

Nitrogen and oxygen gas react as illustrated by the equation given below: N₂ + O₂ → 2NO
Calculate the volume of each reacting gas required to produce 1400cm³ of nitric oxide.

Answer 1

Given react ion is :
N₂ + O₂ → 2NO
According to Gay -Lussac's law in the above reaction 1 volume of nitrogen combines with 1 volume of oxygen to produce 2 volumes of nitric oxide.
i .e. N₂ + O₂ → 2NO
      1 vol. 1 vol. 2 vol.
The volume of nitric oxide produced is = 1400cm³.
Let the volumes of nitrogen and oxygen gases be = x
Then, N₂ + O₂ → 2NO
          x        x    1400cm3
So, x + x = 1400
2x = 1400
x= 1400/ 2 = 700cm³
Hence the volumes of reacting gases i .e. nitrogen and oxygen is 700 cm³ each.