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Question
Calculate the time required to decrease the concentration of reactant of first order reaction from 0.8 M to 0.1 M if rate constant is 0.1155 hour−1.
Options
6 hour
12 hour
18 hour
24 hour
MCQ
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Solution
18 hour
Explanation:
For a first order reaction,
`k = 2.303/t log_10 [A]_0/[A]_t`
`therefore t = 2.303/0.1155 xx log_10 0.8/0.1`
= 19.94 × log10 (8)
= 19.94 × log10 (23)
= 19.94 × 3 log10 (2)
= 19.94 × 3 × 0.301
= 18.0 hour
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