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Question
Calculate the relative molecular masses of the following
(NH4)2 Cr2O7
[At mass : C = 12, H = 1, O = 16, Ci = 35.5, N = 14, Cu = 63.5, S = 32, K = 39, Pt = 195, Ca = 40, P = 31, Mg = 24]
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Solution
For Relative Molecular Mass, (NH₄)₂Cr₂O₇
= 2(14 + 4 × 1) + 2 × 52 + 7 × 16
= 2 × 18 + 104 + 112
= 36 + 216
= 252
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