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Question
Calculate the quantity of heat produced in a 40 Ω resistor carrying a current of 5A in 5 minutes.
Numerical
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Solution
Given:
R = 40 Ω
I = 5 A
t = 5 min = 5 × 60 s = 300 s
Formula:
H = I2Rt
= (5)2 × 40 × 300
= 25 × 40 × 300
= 3,00,000 J
= 3 × 105 J
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Chapter 8: Electric Energy, Power and Household Circuits - EXERCISE-2 [Page 193]
