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Question
Calculate the pH and pOH of 0.0001 M HCl solution.
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Solution
Given: Concentration of HCl solution = 0.0001 M
To find: pH and pOH
Formulae:
- pH = – log10[H3O+]
- pH + pOH = 14
Calculation: HCl is a strong acid. It dissociates almost completely in water as:
\[\ce{HCl_{ (aq)} + H2O_{ (l)} -> H3O^+_{ (aq)} + Cl^-_{ (aq)}}\]
Hence, [H3O+] = c = 0.0001 M = 1 × 10-4 M
From formula (i),
pH = - log10[H3O+] = - log10[1 × 10-4] = 4
From formula (ii),
pH + pOH = 14
∴ pOH = 14 − pH = 14 – 4 = 10
The pH and pOH of 0.0001 M HCl solution are 4 and 10 respectively.
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