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Calculate the pH and pOH of 0.0001 M HCl solution.

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Question

Calculate the pH and pOH of 0.0001 M HCl solution.

Numerical
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Solution

Given: Concentration of HCl solution = 0.0001 M

To find: pH and pOH

Formulae:

  1. pH = – log10[H3O+]
  2. pH + pOH = 14

Calculation: HCl is a strong acid. It dissociates almost completely in water as:

\[\ce{HCl_{ (aq)} + H2O_{ (l)} -> H3O^+_{ (aq)} + Cl^-_{ (aq)}}\]

Hence, [H3O+] = c = 0.0001 M = 1 × 10-4 M

From formula (i),

pH = - log10[H3O+] = - log10[1 × 10-4] = 4

From formula (ii),

pH + pOH = 14

∴ pOH = 14 − pH = 14 – 4 = 10

The pH and pOH of 0.0001 M HCl solution are 4 and 10 respectively.

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Chapter 3: Ionic Equilibria - Short answer questions (Type- I)

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SCERT Maharashtra Chemistry [English] Standard 12 Maharashtra State Board
Chapter 3 Ionic Equilibria
Short answer questions (Type- I) | Q 1
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