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Question
Calculate the percentage composition of KNO3.
[At. wts. are K = 39, N = 14, O = 16]
Numerical
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Solution
Mol. wt. of KNO3 = At. wt. of K + At. wt. of N + 3 × [At. wt. of O]
= 39 + 14 + 3 × [16]
= 39 + 14 + 48
= 101 amu
Percentage of Potassium (K) = `39/101 xx 100` = 38.61%
Percentage of Nitrogen (N) = `14/101 xx 100` = 13.86%
Percentage of Oxygen (O) = `48/101 xx 100` = 47.53%
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