Question

Calculate the molecular weight of Na₂CO₃.

[At. wts. are O = 16, Na = 23, C = 12]

Answer 1

Molecular weight = 2 × (At. wt. of Na) + (At. wt. of C) + 3 × (At. wt. of O)

= 2 × 23 + 12 + 3 × 16

= 46 + 12 + 48

= 106 amu