Advertisements
Advertisements
Question
Calculate the mean of the following data:
| Class | 4 – 7 | 8 – 11 | 12 – 15 | 16 – 19 |
| Frequency | 5 | 4 | 9 | 10 |
Chart
Sum
Advertisements
Solution
Since, given data is not continuous, so we subtract 0.5 from the lower limit and add 0.5 in the upper limit of each class.
Now, we first find the class mark xi of each class and then proceed as follows.
| Class | Class marks `(bb(x_i))` |
Frequency `(bb(f_i))` |
`bb(f_ix_i)` |
| 3.5 – 7.5 | 5.5 | 5 | 27.5 |
| 7.5 – 11.5 | 9.5 | 4 | 38 |
| 11.5 – 15.5 | 13.5 | 9 | 121.5 |
| 15.5 – 19.5 | 17.5 | 10 | 175 |
| `sumf_i = 28` | `sumf_ix_i = 362` |
Therefore, mean `(barx) = (sumf_ix_i)/(sumf_i)`
= `362/28`
= 12.93
Hence, mean of the given data is 12.93.
shaalaa.com
Is there an error in this question or solution?
